×ðÁú¿­Ê±

¾Ûõ¥¶àÔª´¼ÆÊÎöÒªÁì



       ¶àÔª´¼ºÍÒìÇèËáõ¥ÊÇÕû¸ö¾Û°±õ¥·´Ó¦µÄ×îÖ÷ÒªÁ½ÖÖÔ­ÁÏ¡£¶ø¾Ûõ¥¶àÔª´¼¾ÍÊÇÒ»ÖÖ³£ÓõĶàÔª´¼Ö®Ò»¡£ÐèÒª²â¶¨¾Ûõ¥¶àÔª´¼µÄËáÖµºÍôÇÖµ£¬¶Ô¿ØÖƾ۰±õ¥·´Ó¦µÄÖØÒªÐÔÊDz»ÑÔ¶øÓ÷µÄ¡£ôÇÖµ·´Ó¦µÄ¾Ûõ¥¶àÔª´¼µÄ·Ö×ÓÁ¿£¬ËáÖµ¾ÞϸӰÏìÓëÒìÇèËáõ¥µÄ·´Ó¦ÐÔ¡£


Ò»£º¾Ûõ¥¶àÔª´¼ËáÖµ

       Ò»°ã£¬¾Ûõ¥¶àÔª´¼³ÊÈõËáÐÔ£¬ËáÖµµÄ¼ÄÒåÊÇ£ºÃ¿¿ËÑùÆ·ÖÐËáÐÔÉí·ÖËùÏûºÄµÄKOHµÄĦ¶ûÖÊÁ¿£¨mg£©¡£µ¥Î»ÊÇ£ºmgKOH/g¡£

1£©²âÊÔ¾Ûõ¥¶àÔª´¼ËáÖµ²Ù×÷°ì·¨£º
       ¾«È·³ÆÈ¡¾Ûõ¥¶àÔª´¼ÑùÆ·2-4g£¬¼ÓÈë»ìÏýÊÔ¼Á50mlÈÜÒº£¬³ä·ÖÒ¡¾ùÔÈ£¬¼Ó2-4 d PPָʾ¼Á£¬ÒÔ0.1N ±ê×¼KOHÈÜÒº½øÐе樣¬Ö±ÖÁ·ºÆð·ÛºìÉ«15sÎȶ¨ÎªµÎ¶¨Öյ㣬¼Í¼µÎ¶¨Öµ¡£Í¬Ê±×ö¿Õ°×ʵÑé¡£
2£©ÅÌË㹫ʽ£º
AV£¨ËáÖµKOHmg/g£©=56.1×f×£¨VÑù-V¿Õ£©÷MÑùÖØ
F£º0.1N ±ê×¼KOHÈÜÒºµÄÐÞÕýÖµ¡£
56.1£ºKOHµÄĦ¶ûÖÊÁ¿¡£
3£©ÆÊÎöÊÔ¼ÁµÄÅäÖÆ£º        0.1N±ê×¼KOHÈÜÒºµÄÅäÖÆ£º¾«È·³ÆÈ¡ÆÊÎö¼¶KOH3.3±0.0001g£¬¼ÓÕôÁóË®ÖÁ500ml£¬Ò¡Ôȱ¸Óá£
       0.1N±ê×¼KOHÈÜÒºµÄ±ê¶¨£¨ÐÞÕýÖµf£©£º ¾«È·³ÆÈ¡°±»ù»ÇËá1.5±0.0001gÓÚÈý½ÇÆ¿ÄÚ£¬¼ÓÊÊÁ¿ÕôÁóË®£¨Ô¼90ml£©½øÐÐÈܽ⣬µÎÈë2-4 d PPָʾ¼Á£¬Ò»ËùÅäÖÆµÄ0.1N±ê×¼KOHÈÜÒº½øÐе樣¬¼Í¼µÎ¶¨Öµ£¬

ÔòFÖµ=W/ V × 103
ÆäÖÐW£º°±»ù»ÇËá³ÆÈ¡Á¿    V£ºµÎ¶¨Öµ

       »ìÏýÊÔ¼ÁµÄÅäÖÆ£ºaÎÞË®ÒÒ´¼Óë´×ËáÒÒõ¥Ìå»ý±È1£º1»ìÏý¾ùÔȼ´¿É£»b¼×±½Óë´×ËáÒÒõ¥Ìå»ý±È1£º1»ìÏý¾ùÔÈÒà¿É¡£


¶þ£º¾Ûõ¥¶àÔª´¼µÄôÇÖµ
       ÔÚ¾Û°±õ¥ºÏ³ÉÖУ¬¾Ûõ¥¶àÔª´¼ôÇÖµÊÇÒ»¸öÖØÒªÖ¸±ê¡£Ö»ÓÐÃ÷È·Á˽â¾Ûõ¥¶àÔª´¼µÄôÇÖµ£¬²Å»ªÈ·¶¨¾Ûõ¥¶àÔª´¼µÄ·Ö×ÓÁ¿¡£ôÇÖµ¼ÄÒåÊÇ£ºÃ¿¿ËÑùÆ·ËùÏûºÄµÄKOHĦ¶ûÖÊÁ¿Êý¡£µ¥Î»ÊÇmgKOH/g¡£
1£©²âÊÔ¾Ûõ¥¶àÔª´¼ôÇÖµµÄ²Ù×÷°ì·¨£¨±½ôû-ßÁष¨£©¡£
       ¾«È·³ÆÈ¡¾Ûõ¥¶àÔª´¼ÑùÆ·2-5gÓÚÄ¥¿Ú×¶ÐÎÈý½ÇÆ¿ÄÚ£¬ÓÃÒÆÒº¹Ü¾«È·¼ÓÈë±½ôû-ßÁà¤õ£»¯¼Á20ml¡£Ò¡ÔȺóÓÚºæÏ䣨120¡æ£©¼ÓÈÈһСʱ£¬È¡³öÀäÈ´ºó£¬¼ÓÈëÕôÁóË®90mlÕðµ´£¬Ê¹Ö®³ä·ÖÈܽâ¡£ÔÙÒÔ5mlõ£»¯¼Á¶ÔÆ¿±Ú½øÐÐÇåÏ´¡£¼Ó2-4dPPָʾ¼Á£¬ÒÔ0.5N±ê×¼KOHÈÜÒº½øÐе樣¬Ö±ÖÁ·ºÆð·ÛºìÉ«15sÎȶ¨ÎªµÎ¶¨Öյ㣬¼Í¼µÎ¶¨Öµ£¬Í¬Ò»ÑùÆ·»®·Ö×öÁ½´Î¡£²¢×ö¿Õ°×ʵÑé¡£
2£©ÅÌË㹫ʽ£º

OH£¨ôÇÖµKOHmg/g£©=(V¿Õ-VÑù)×f×56.1/mÑùÁ¿×0.5
F£º0.5N ±ê×¼KOHÈÜÒºµÄÐÞÕýÖµ¡£
56.1£ºKOHµÄĦ¶ûÖÊÁ¿¡£
3£©ÆÊÎöÊÔ¼ÁµÄÅäÖÆ£º
       0.5N±ê×¼KOHÈÜÒºµÄÅäÖÆ£º¾«È·³ÆÈ¡ÆÊÎö¼¶KOH16.5±0.0001g£¬¼ÓÕôÁóË®ÖÁ500ml£¬Ò¡Ôȱ¸Óá£
       0.5N±ê×¼KOHÈÜÒºµÄ±ê¶¨£¨ÐÞÕýÖµf£©£º¾«È·³ÆÈ¡°±»ù»ÇËá1.5±0.0001gÓÚÈý½ÇÆ¿ÄÚ£¬¼ÓÊÊÁ¿ÕôÁóË®£¨Ô¼90ml£©½øÐÐÈܽ⣬µÎÈë2-4dPPָʾ¼Á£¬Ò»ËùÅäÖÆµÄ0.5N±ê×¼KOHÈÜÒº½øÐе樣¬¼Í¼µÎ¶¨Öµ£¬Ôò FÖµ=W/ V × 20.6
ÆäÖÐW£º°±»ù»ÇËá³ÆÈ¡Á¿   V£ºµÎ¶¨Öµ
        ±½ôû-ßÁà¤õ£»¯¼ÁÅäÖÆ£º³ÆÈ¡42gÁÚ±½¶þ¼×ËáôûºÍ6gßäßòÈÜÓÚ300mlßÁà¤ÖУ¬»ìÏý¾ùÔȺóÖü´æÓÚ×ØÉ«Æ¿ÄÚ±¸Óá£
×¢£º±¾·¨¿ÉÓÃÓÚ¾ÛÃÑÖ®ËáÖµºÍôÇÖµÆÊÎö¼ì²â¡£ËùµÃÊý¾Ý±ÈÆäËûÒªÁìÏà¶ÔÒª¿É¿¿¡£


Èý£º¾Ûõ¥¶àÔª´¼ÆäËüÆÊÎö
1£©·Ö×ÓÁ¿
M·Ö×ÓÁ¿=56.1× n ×1000/ ¾Ûõ¥¶àÔª´¼Ð£ÕýôÇÖµ 

¾Ûõ¥¶àÔª´¼Ð£ÕýôÇÖµ=ôÇÖµ+ËáÖµ
2£©Ë®·ÖÓÃË®·ÝÆÊÎöÒǼì²âÖ®¡£
3£©É«¶ÈÓñÈÉ«·¨ÆÊÎöÖ®¡£

4£©Õ³¶ÈÓÃÕ³¶ÈÒDzⶨ¡£

ÍøÕ¾µØÍ¼